If A and B are non-empty subsets of a set, then (A-B) ∪(B-A) equals to

Question

If A and B are non-empty subsets of a set, then (A-B) ∪(B-A) equals to (A) (A ∩ B) ∪(A ∪ B) (B) (A ∪ B)-(A-B) (C) (A ∪ B)-(A ∩ B) (D) (A ∪ B)-B

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/8ee6297d8e6648b1bdb1cab1eb7c3815-.png" /> Clearly, (A ∪ B)-(A ∩ B)=(A-B) ∪(B-A)

Q. If $A$ and $B$ are non-empty subsets of a set, then $(A - B) \cup (B - A)$ equals to

$(A \cap B) \cup (A \cup B)$

$(A \cup B) - (A - B)$

$(A \cup B) - (A \cap B)$

$(A \cup B) - B$

Clearly, $(A \cup B) - (A \cap B) = (A - B) \cup (B - A)$

Q. If A and B are non-empty subsets of a set, then (A−B)∪(B−A) equals to

(A∩B)∪(A∪B)

(A∪B)−(A−B)

(A∪B)−(A∩B)

(A∪B)−B