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Mathematics
If A and B are non-empty subsets of a set, then (A-B) ∪(B-A) equals to
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Q. If $A$ and $B$ are non-empty subsets of a set, then $(A-B) \cup(B-A)$ equals to
Sets
A
$(A \cap B) \cup(A \cup B)$
B
$(A \cup B)-(A-B)$
C
$(A \cup B)-(A \cap B)$
D
$(A \cup B)-B$
Solution:
Clearly, $(A \cup B)-(A \cap B)=(A-B) \cup(B-A)$
