Question

If $A$ and $B$ are $2$ square matrices of the same order, then $(A-B{)}^2$ is:

• A. $A^2-AB-BA+B^2$
• B. $A^2-2BA+B^2$
• C. $A^2-2AB+B^2$
• D. $A^2-B^2$

Answer 1

Answer: (A)

$\therefore (A-B{)}^2=(A-B)(A-B)$
$=A^2-AB-BA+B^2$