if A = [4&1&0 1&-2&2] , B = [2&0&-1 3&1&x] , C = [1 2 1] and D =[15+x 1] such that (2A -3B)C=D, then x =

Question

if A = [4&1&0 1&-2&2] , B = [2&0&-1 3&1&x] , C = [1 2 1] and D =[15+x 1] such that (2A -3B)C=D, then x = (A) 3 (B) -4 (C) -6 (D) 6

Tardigrade Admin · Accepted Answer

(2A - 3B) C =D ⇒ [2[4&1&0 1&-2&2]-3 [2&0&-1 3&1&x]] [1 2 1] =[15+x 1] ⇒ [2&2&3 -7&-7&4-3x] [1 2 1] =[15+x 1] ⇒ [9 -17-3x] = [15+x 1] ⇒ x = -6

Q. if $A = [41 1 - 2 02], B = [2301 - 1 x], C = ⎣ ⎡ 121 ⎦ ⎤$ and $D = [15 + x 1]$ such that $(2 A - 3 B) C = D$ , then $x$ =