Q. if $A = \begin{bmatrix}4&1&0\\ 1&-2&2\end{bmatrix} , B = \begin{bmatrix}2&0&-1\\ 3&1&x\end{bmatrix} , C = \begin{bmatrix}1\\ 2\\ 1\end{bmatrix}$ and $D =\begin{bmatrix}15+x\\ 1\end{bmatrix}$ such that $(2A -3B)C=D$, then $x$ =
Matrices
Solution: