if A = [2&1 -1&2], B = [1&-2 2&1], C = [1&-3 2&1], then

Question

if A = [2&1 -1&2], B = [1&-2 2&1], C = [1&-3 2&1], then (A) A + B = B + A and A + (B + C) = (A + B) + C  (B) A+ B = B +A and AC = BC  (C) A + B = B + A and AB = BC  (D) AC = BC and A = BC

Tardigrade Admin · Accepted Answer

In option (a), there are two laws, commutative law and associative law, which are satisfied by all matrices. Thus, option (a) is correct.

Q. if $A = [2 - 1 12], B = [12 - 2 1], C = [12 - 3 1],$ then

$A + B = B + A$ and $A + (B + C) = (A + B) + C$

$A + B = B + A$ and $A C = BC$

$A + B = B + A$ and $A B = BC$

$A C = BC$ and $A = BC$

In option (a), there are two laws, commutative law and associative law, which are satisfied by all matrices. Thus, option (a) is correct.

Q. if A=[2−1​12​],B=[12​−21​],C=[12​−31​], then

A+B=B+A and A+(B+C)=(A+B)+C

A+B=B+A and AC=BC

A+B=B+A and AB=BC

AC=BC and A=BC

In option (a), there are two laws, commutative law and associative law, which are satisfied by all matrices. Thus, option (a) is correct.

Q. if $A = [2 - 1 12], B = [12 - 2 1], C = [12 - 3 1],$ then

$A + B = B + A$ and $A + (B + C) = (A + B) + C$

$A + B = B + A$ and $A C = BC$

$A + B = B + A$ and $A B = BC$

$A C = BC$ and $A = BC$