If A= 1,3,5,7,9,11,13,15,17 B= 2, 4,6,8,10,12,14,16,18 and N, the set of natural numbers is the universal set, then A prime ∪[(A ∪ B) ∩ B prime] is

Question

If A= 1,3,5,7,9,11,13,15,17 B= 2, 4,6,8,10,12,14,16,18 and N, the set of natural numbers is the universal set, then A prime ∪[(A ∪ B) ∩ B prime] is (A) A (B) A prime (C) B (D) N.

Tardigrade Admin · Accepted Answer

(A ∪ B) ∩ B prime=A text as A ∩ B=φ ⇒ A prime ∪[(A ∪ B) ∩ B prime]=A prime ∪ A= N .

Q. If $A = {1, 3, 5, 7, 9, 11, 13, 15, 17}, B = {2$ , $4, 6, 8, 10, 12, 14, 16, 18}$ and $N$ , the set of natural numbers is the universal set, then $A^{'} \cup [(A \cup B) \cap B^{'}]$ is

$A$

$A^{'}$

$B$

$N$ .

$(A \cup B) \cap B^{'} = A as A \cap B = ϕ$
$\Rightarrow A^{'} \cup [(A \cup B) \cap B^{'}] = A^{'} \cup A = N .$

Q. If A={1,3,5,7,9,11,13,15,17},B={2, 4,6,8,10,12,14,16,18} and N, the set of natural numbers is the universal set, then A′∪[(A∪B)∩B′] is

A

A′

B

N.

(A∪B)∩B′=A as A∩B=ϕ ⇒A′∪[(A∪B)∩B′]=A′∪A=N.

Q. If $A = {1, 3, 5, 7, 9, 11, 13, 15, 17}, B = {2$ , $4, 6, 8, 10, 12, 14, 16, 18}$ and $N$ , the set of natural numbers is the universal set, then $A^{'} \cup [(A \cup B) \cap B^{'}]$ is

$A$

$A^{'}$

$B$

$N$ .

$(A \cup B) \cap B^{'} = A as A \cap B = ϕ$
$\Rightarrow A^{'} \cup [(A \cup B) \cap B^{'}] = A^{'} \cup A = N .$