If A = [1&-2 3&0], B = [-1&4 2&3] and C = [0&1 -1&0] then 5A - 3B + 2C is equal to

Question

If A = [1&-2 3&0], B = [-1&4 2&3] and C = [0&1 -1&0] then 5A - 3B + 2C is equal to (A) [8&20 7&9] (B) [8& - 20 7& - 9] (C) [ - 8&20 - 7&9] (D) [8& 7 -20 - 9]

Tardigrade Admin · Accepted Answer

Given A = [1&-2 3&0] , B = [-1&4 2&3] C = [0&1 -1&0] Consider 5A - 3B + 2C = 5 [1&-2 3&0] - 3 [-1&4 2&3] + 2 [0&1 -1&0] = [5 &-10 15&0] - [-3&12 6&9] + [0&2 -2&0] = [8&-22 9&-9] + [0&2 -2&0] = [8&-20 7&-9]

Q. If $A = [13 - 2 0], B = [- 1 2 43]$ and $C = [0 - 1 10]$ then 5A - 3B + 2C is equal to

$[87209]$

$[87 - 20 - 9]$

$[- 8 - 7 209]$

$[8 - 20 7 - 9]$

Given $A = [13 - 2 0], B = [- 1 2 43] C = [0 - 1 10]$
Consider 5A - 3B + 2C
$= 5 [13 - 2 0] - 3 [- 1 2 43] + 2 [0 - 1 10]$
$= [515 - 10 0] - [- 3 6 129] + [0 - 2 20]$
$= [89 - 22 - 9] + [0 - 2 20] = [87 - 20 - 9]$

Q. If A=[13​−20​],B=[−12​43​] and C=[0−1​10​] then 5A - 3B + 2C is equal to

[87​209​]

[87​−20−9​]

[−8−7​209​]

[8−20​7−9​]