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Question
Mathematics
If a ≠ 0 and the line 2bx + 3cy + 4d = 0 passes through the points of intersection of the parabolas y2 = 4ax and x2 = 4ay , then
Q. If
a
=
0
and the line
2
b
x
+
3
cy
+
4
d
=
0
passes through the points of intersection of the parabolas
y
2
=
4
a
x
and
x
2
=
4
a
y
, then
1850
201
AIEEE
AIEEE 2004
Conic Sections
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A
d
2
+
(
2
b
+
3
c
)
2
=
0
100%
B
d
2
+
(
3
b
+
2
c
)
2
=
0
0%
C
d
2
+
(
2
b
−
3
c
)
2
=
0
0%
D
d
2
+
(
3
b
−
2
c
)
2
=
0
0%
Solution:
Points of intersection of given parabolas are
(
0
,
0
)
and
(
4
a
,
4
a
)
⇒
equation of line passing through these points is
y
=
x
On comparing this line with the given line
2
b
x
+
3
cy
+
4
d
=
0
, we get
d
=
0
and
2
b
+
3
c
=
0
⇒
(
2
b
+
3
c
)
2
+
d
2
=
0
.