If 92U238 undergoes successively 8 α-decays and 6 β-decays, then the resulting nucleus is

Question

If 92U238 undergoes successively 8 α-decays and 6 β-decays, then the resulting nucleus is (A)  82 U 210 (B)  82 U 208 (C)  8 2 U 214 (D)  82 U 206

Tardigrade Admin · Accepted Answer

Due to 8 α -decays, the atomic mass decreases by 32 and atomic number will reduce by 16 . And due to 6 β -decays, the atomic number increases by 6 . Therefore resulting nucleus is 82 U 206.

Q. If $_{92} U^{238}$ undergoes successively $8 α$ -decays and $6 β$ -decays, then the resulting nucleus is

$_{82} U^{210}$

$_{82} U^{208}$

$_{82} U^{214}$

$_{82} U^{206}$

Due to $8 α$ -decays, the atomic mass decreases by $32$ and atomic number will reduce by $16.$
And due to $6 β$ -decays, the atomic number increases by $6$ .
Therefore resulting nucleus is $_{82} U^{206}$ .

Q. If 92​U238 undergoes successively 8α-decays and 6β-decays, then the resulting nucleus is

82​U210

82​U208

82​U214

82​U206