If 62.5 × 1018 electrons per second are flowing through a wire of area of cross-section 0.1 m 2, the value of current flowing will be

Question

If 62.5 × 1018 electrons per second are flowing through a wire of area of cross-section 0.1 m 2, the value of current flowing will be (A) 1 A (B) 0.1 A (C) 10 A (D) 0.11 A

Tardigrade Admin · Accepted Answer

i=(n e/t)=(62.5 × 1018 × 1.6 × 10-19/1)=10 amperes

Q. If $62.5 \times 1 0^{18}$ electrons per second are flowing through a wire of area of cross-section $0.1 m^{2}$ , the value of current flowing will be

1 A

0.1 A

10 A

0.11 A

$i = \frac{n e}{t} = \frac{62.5 \times 1 0 ^{18} \times 1.6 \times 1 0 ^{- 19}}{1} = 10$ amperes

Q. If 62.5×1018 electrons per second are flowing through a wire of area of cross-section 0.1m2, the value of current flowing will be

1 A

0.1 A

10 A

0.11 A

i=tne​=162.5×1018×1.6×10−19​=10 amperes

Q. If $62.5 \times 1 0^{18}$ electrons per second are flowing through a wire of area of cross-section $0.1 m^{2}$ , the value of current flowing will be

$i = \frac{n e}{t} = \frac{62.5 \times 1 0 ^{18} \times 1.6 \times 1 0 ^{- 19}}{1} = 10$ amperes