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  4. If 62.5 × 1018 electrons per second are flowing through a wire of area of cross-section 0.1 m 2, the value of current flowing will be

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Q. If $62.5 \times 10^{18}$ electrons per second are flowing through a wire of area of cross-section $0.1 m ^{2}$, the value of current flowing will be

Current Electricity

Solution:

$i=\frac{n e}{t}=\frac{62.5 \times 10^{18} \times 1.6 \times 10^{-19}}{1}=10$ amperes