Q.
If 5% of the energy supplied to a bulb is irradiated as visible light, how many quanta are emitted per second by a 100 W lamp? (Assume wavelength of visible light as 5.6×10−5 cm)
7214
191
Dual Nature of Radiation and Matter
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Solution:
Energy radiated as visible light = 1005×100=5 J/s
Let n be the number of photons emitted per second. Then,
nhv = E = 5 ∴n=hc5λ=(6.62×10−34)(3×108)5×5.6×10−7
= 1.4×1019