If 4x+i(3x-y)=3+i(-6), where x and y are real numbers, then find the values of x and y respectively.

Question

If 4x+i(3x-y)=3+i(-6), where x and y are real numbers, then find the values of x and y respectively. (A) 1/4, 3/4 (B) 3/4, 33/4 (C) 33/4, -3/4 (D) -3/4, -33/4

Tardigrade Admin · Accepted Answer

We have, 4x+i(3x-y)=3+i(-6) Equating the real and imaginary parts, we get 4x = 3, 3 x - y =-6 which, on solving simultaneously, gives x=(3/4) and y=(33/4)⋅

Q. If $4 x + i (3 x - y) = 3 + i (- 6)$ , where $x$ and $y$ are real numbers, then find the values of $x$ and $y$ respectively.

$1/4$ , $3/4$

$3/4$ , $33/4$

$33/4$ , $- 3/4$

$- 3/4$ , $- 33/4$

We have, $4 x + i (3 x - y) = 3 + i (- 6)$
Equating the real and imaginary parts, we get
$4 x = 3$ , $3 x - y = - 6$
which, on solving simultaneously, gives
$x = \frac{3}{4}$ and $y = \frac{33}{4} \cdot$

Q. If 4x+i(3x−y)=3+i(−6), where x and y are real numbers, then find the values of x and y respectively.

1/4, 3/4

3/4, 33/4

33/4, −3/4

−3/4, −33/4