If 3x = 4 x - 1 then x is equal to

Question

If 3x = 4 x - 1 then x is equal to (A)  ( 2 log3 2/ 2 log3 2 - 1) (B)  ( 2/ 2 log2 3 ) (C)  ( 1/ 1 - log4 3 )  (D)  ( 2 log2 3 / 2 log2 3 - 1)

Tardigrade Admin · Accepted Answer

3x = 4 x - 1 Taking log3 on both sides, we get ⇒ x log3 3 = (x - 1) log34 ⇒ x = 2 log3 2 . x - log3 4 ⇒ x ( 1 - 2 log3 2) = - 2 log3 2 ⇒ x = ( 2 log3 2 / 2 log3 2 - 1) x = (1/ 1 - (1) 2 log3 2 ) = (1/ 1 - (1) log3 4 ) = (1/ 1 - log4 3 ) = (2/ 2 - log2 3) = (1/ 1 - (1)2 log2 3 ) = (1/ 1 - log4 3 )

Q. If $3^{x} = 4^{x - 1}$ then x is equal to

$\frac{2 l o g _{3} 2}{2 l o g _{3} 2 - 1}$

$\frac{2}{2 l o g _{2} 3}$

$\frac{1}{1 - l o g _{4} 3}$

$\frac{2 l o g _{2} 3}{2 l o g _{2} 3 - 1}$

Q. If 3x=4x−1 then x is equal to

2log3​2−12log3​2​

2log2​32​

1−log4​31​

2log2​3−12log2​3​

3x=4x−1 Taking log3​ on both sides, we get ⇒xlog3​3=(x−1)log34​⇒x=2log3​2.x−log3​4 ⇒x(1−2log3​2)=−2log3​2⇒x=2log3​2−12log3​2​ x = 1−2log3​21​1​=1−log3​41​1​=1−log4​31​=2−log2​32​ = 1−21​log2​31​=1−log4​31​

Q. If $3^{x} = 4^{x - 1}$ then x is equal to

$\frac{2 l o g _{3} 2}{2 l o g _{3} 2 - 1}$

$\frac{2}{2 l o g _{2} 3}$

$\frac{1}{1 - l o g _{4} 3}$

$\frac{2 l o g _{2} 3}{2 l o g _{2} 3 - 1}$