Question

If $-3x+17<-13$, then

• A. $x\in (10,\infty )$
• B. $x\in [-\infty ,10)$
• C. $10x\in (-10,10)$
• D. $x\in (-\infty ,-10)\cup (10,\infty )$

Answer 1

Answer: (A)

We have, $-3x+17<-13$
Subtracting 17 from both sides,
$-3x<-13-17$
$\Rightarrow -3x<-30$
Dividing both sides by $(-3),$
$x>10$
$\Rightarrow x\in (10,\infty )$