Question

If $-3 x+17<-13$, then

• A. $x \in(10, \infty)$
• B. $x \in[-\infty, 10)$
• C. $10 x \in(-10,10)$
• D. $x \in(-\infty,-10) \cup(10, \infty)$

Answer 1

Answer: (A)

We have, $-3 x+17<-13$
Subtracting 17 from both sides,
$ -3 x<-13-17 $
$\Rightarrow -3 x<-30 $
Dividing both sides by $ (-3), $
$x >10 $
$\Rightarrow x \in(10, \infty)$