If 2n+3C2n - 2n+2C2n-1 = 15 (2n+1), then n=

Question

If 2n+3C2n - 2n+2C2n-1 = 15 (2n+1), then n=  (A) 13 (B) 14 (C) 27 (D) 15

Tardigrade Admin · Accepted Answer

(⌊2n+3 /⌊2n ⌊3) -( ⌊2n+2/⌊2n-1⌊3) = 15(2n+1) ⇒ ((2n+2)(2n+1)/2) = 15(2n+1) ⇒ n+1=15 ⇒ n=14.

Q. If $^{2 n + 3} C_{2 n} -^{2 n + 2} C_{2 n - 1} = 15 (2 n + 1)$ , then $n =$