If 25 ml of 0.25 M NaCl solution is diluted with water to a volume of 500 ml the new concentration of the solution is

Question

If 25 ml of 0.25 M NaCl solution is diluted with water to a volume of 500 ml the new concentration of the solution is (A) 0.0125 M (B) 0.167 M (C) 0.833 M (D) 0.0167 M

Tardigrade Admin · Accepted Answer

M1V1=M2V2, M2=(0.25×25/500) =0.0125

Q. If 25 ml of 0.25 M NaCl solution is diluted with water to a volume of 500 ml the new concentration of the solution is

0.0125 M

0.167 M

0.833 M

0.0167 M

$M_{1} V_{1} = M_{2} V_{2}$ ,
$M_{2} = \frac{0.25 \times 25}{500}$
$= 0.0125$

Q. If 25 ml of 0.25 M NaCl solution is diluted with water to a volume of 500 ml the new concentration of the solution is

0.0125 M

0.167 M

0.833 M

0.0167 M

M1​V1​=M2​V2​, M2​=5000.25×25​ =0.0125

$M_{1} V_{1} = M_{2} V_{2}$ ,
$M_{2} = \frac{0.25 \times 25}{500}$
$= 0.0125$