If 200 MeV energy is released in the fission of a single nucleus of 92 U235, how many fissions must occur per second to produce a power of 1 kW ?

Question

If 200 MeV energy is released in the fission of a single nucleus of 92 U235, how many fissions must occur per second to produce a power of 1 kW ? (A)  3.12× 1013  (B)  3.12× 103 (C)  3.1× 1017  (D)  3.12× 1019

Tardigrade Admin · Accepted Answer

Total energy/s =1000 J Energy released/fission =200 MeV =200 × 1.6 × 10-13 J =3.2 × 10-11 J ∴ Number of fission/s =(1000/3.2 × 10-11) =3.2 × 1013

Q. If $200 M e V$ energy is released in the fission of a single nucleus of $_{92} U^{235}$ , how many fissions must occur per second to produce a power of $1 kW$ ?

$3.12 \times 1 0^{13}$

$3.12 \times 1 0^{3}$

$3.1 \times 1 0^{17}$

$3.12 \times 1 0^{19}$

Total energy/s $= 1000 J$
Energy released/fission $= 200 M e V$
$= 200 \times 1.6 \times 1 0^{- 13} J$
$= 3.2 \times 1 0^{- 11} J$
$∴$ Number of fission/s
$= \frac{1000}{3.2 \times 1 0 ^{- 11}}$
$= 3.2 \times 1 0^{13}$

Q. If 200MeV energy is released in the fission of a single nucleus of 92​U235, how many fissions must occur per second to produce a power of 1kW ?

3.12×1013

3.12×103

3.1×1017

3.12×1019