Question

If $2+i\sqrt{3}$ is a root of the equation $x^2+px+q=0$, where $p$ and $q$ are real, then $(p,q)=$

• A. (-4,7)
• B. (4,-7)
• C. (4,7)
• D. (-4,-7)

Answer 1

Answer: (A)

Since $2+i\sqrt{3}$ is a root, therefore, $2-i\sqrt{3}$ will be other root. Now sum of the roots $=4=-p$ and product of roots $=7=q.$ Hence $(p,q)=(-4,7)$