Question

If $2.8g$ of a metal oxide contains $0.8g$ oxygen, then the equivalent mass of the metal is

• A. 16 g
• B. 20 g
• C. 12 g
• D. 8 g

Answer 1

Answer: (B)

${\left(\frac{W}{E}\right)}_M={\left(\frac{W}{E}\right)}_O$
$\frac{2}{E_M}=\frac{0.8}{8}$
$E_M=20g$