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  4. If 2.8 g of a metal oxide contains 0.8 g oxygen, then the equivalent mass of the metal is

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Q. If $2.8 \,g$ of a metal oxide contains $0.8 \,g$ oxygen, then the equivalent mass of the metal is

Solution:

$\left(\frac{W}{E}\right)_{M}=\left(\frac{W}{E}\right)_{O}$
$\frac{2}{E_{M}}=\frac{0.8}{8}$
$E_{M}=20\, g$