If 150 kJ of energy is needed for muscular work to walk a distance of one km, then how much of glucose one has to consume to walk a distance of provided only 30% energy is available for muscular work. The enthalpy of combustionof glucose is 3000 kJ mol-1'

Question

If 150 kJ of energy is needed for muscular work to walk a distance of one km, then how much of glucose one has to consume to walk a distance of provided only 30% energy is available for muscular work. The enthalpy of combustionof glucose is 3000 kJ mol-1' (A) 75 g (B) 30 g (C) 180 g (D) 150 g

Tardigrade Admin · Accepted Answer

Energy consumed for walking a distance of 5 km
= 150

\times

5 kJ = 750 kJ
1 mole of glucose,

C_{6} H_{12} O_{6}

(180 g) gives
theoretically energy = 3000 kJ
Actual energy available =

\frac{30}{100} \times

3000 = 900 kJ
Thus for 900 kJ of energy, glucose required = 180 g

∴

for 750 kJ of energy, glucose required
=

\frac{180}{900} \times 750

= 150 g

Q. If 150 kJ of energy is needed for muscular work to walk a distance of one km, then how much of glucose one has to consume to walk a distance of provided only 30% energy is available for muscular work. The enthalpy of combustionof glucose is 3000 kJmol−1'

75 g

30 g

180 g

150 g

Q. If 150 kJ of energy is needed for muscular work to walk a distance of one km, then how much of glucose one has to consume to walk a distance of provided only 30% energy is available for muscular work. The enthalpy of combustionof glucose is 3000 $k J m o l^{- 1}$ '