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  4. If 150 kJ of energy is needed for muscular work to walk a distance of one km, then how much of glucose one has to consume to walk a distance of provided only 30% energy is available for muscular work. The enthalpy of combustionof glucose is 3000 kJ mol-1'

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Q. If 150 kJ of energy is needed for muscular work to walk a distance of one km, then how much of glucose one has to consume to walk a distance of provided only 30% energy is available for muscular work. The enthalpy of combustionof glucose is 3000 $kJ mol^{-1}$'

Thermodynamics

Solution:

Energy consumed for walking a distance of 5 km
= 150 $\times$ 5 kJ = 750 kJ
1 mole of glucose, $C_6H_{12}O_6$ (180 g) gives
theoretically energy = 3000 kJ
Actual energy available = $\frac{30}{100} \times $ 3000 = 900 kJ
Thus for 900 kJ of energy, glucose required = 180 g
$\therefore $ for 750 kJ of energy, glucose required
= $\frac{180}{900} \times 750 $ = 150 g