If 12 tickets numbered 0,1,2, ldots ldots . .11 are placed in a bag, and three are drawn out, then the chance that the sum of the numbers on them is equal to 12 is -

Question

If 12 tickets numbered 0,1,2, ldots ldots . .11 are placed in a bag, and three are drawn out, then the chance that the sum of the numbers on them is equal to 12 is - (A) (2/3) (B) (1/5) (C) (3/59) (D) (3/55)

Tardigrade Admin · Accepted Answer

Favourable no. of ways =12 total no. of ways =220 P=(12/220)=(3/55)

Q. If $12$ tickets numbered $0, 1, 2, \dots\dots ..11$ are placed in a bag, and three are drawn out, then the chance that the sum of the numbers on them is equal to $12$ is -

$\frac{2}{3}$

$\frac{1}{5}$

$\frac{3}{59}$

$\frac{3}{55}$

Favourable no. of ways $= 12$
total no. of ways $= 220$
$P = \frac{12}{220} = \frac{3}{55}$

Q. If 12 tickets numbered 0,1,2,……..11 are placed in a bag, and three are drawn out, then the chance that the sum of the numbers on them is equal to 12 is -

32​

51​

593​

553​