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  4. If 12 tickets numbered 0,1,2, ldots ldots . .11 are placed in a bag, and three are drawn out, then the chance that the sum of the numbers on them is equal to 12 is -

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Q. If $12$ tickets numbered $0,1,2, \ldots \ldots . .11$ are placed in a bag, and three are drawn out, then the chance that the sum of the numbers on them is equal to $12$ is -

Probability - Part 2

Solution:

Favourable no. of ways $=12$
total no. of ways $=220$
$P=\frac{12}{220}=\frac{3}{55}$