If 100 mL of 10 M NaOH solution is diluted to 1.0 L,the resulting solution contains

Question

If 100 mL of 10 M NaOH solution is diluted to 1.0 L,the resulting solution contains (A) 1 mole of NaOH (B) 0.1 mole of NaOH (C) 10.0 mole of NaOH (D) 0.05 mole of NaOH

Tardigrade Admin · Accepted Answer

No. of moles = ((100 mL) × (1 mol L-1)/(1000 mL L-1)) = 0.1 mol ∴ the given solution contains NaOH = 0.1 mol

Q. If 100 mL of 10 M NaOH solution is diluted to 1.0 L,the resulting solution contains

1 mole of NaOH

0.1 mole of NaOH

10.0 mole of NaOH

0.05 mole of NaOH

No. of moles = $\frac{( 100 m L ) \times ( 1 m o l L ^{- 1} )}{( 1000 m L L ^{- 1} )}$
= 0.1 mol
$∴$ the given solution contains NaOH = 0.1 mol

Q. If 100 mL of 10 M NaOH solution is diluted to 1.0 L,the resulting solution contains

1 mole of NaOH

0.1 mole of NaOH

10.0 mole of NaOH

0.05 mole of NaOH

No. of moles = (1000mLL−1)(100mL)×(1molL−1)​ = 0.1 mol ∴ the given solution contains NaOH = 0.1 mol

No. of moles = $\frac{( 100 m L ) \times ( 1 m o l L ^{- 1} )}{( 1000 m L L ^{- 1} )}$
= 0.1 mol
$∴$ the given solution contains NaOH = 0.1 mol