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Q. If 100 mL of 10 M NaOH solution is diluted to 1.0 L,the resulting solution contains

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Solution:

No. of moles = $\frac{(100 \, mL) \times (1 \, mol \, L^{-1})}{(1000 \, mL \,L^{-1})}$
= 0.1 mol
$\therefore $ the given solution contains NaOH = 0.1 mol