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Complex Numbers and Quadratic Equations
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Solution:
If (1−i)n=2n ....(i)
We know that, if two complex numbers are equal, their modulus must also be equal.
Therefore, from Eq. (i), we have ∣(1−i)∣n=∣2n∣ ⇒∣1−i∣n−∣2∣n(2n>0) ⇒[12+(−1)2]n=2n ⇒(2)n=2n ⇒22n=2n ⇒2n=n ⇒n=0