If 1 g of hydrogen is converted into 0.993 g of Helium, in the thermo nuclear reaction, the Energy released in the reaction is:

Question

If 1 g of hydrogen is converted into 0.993 g of Helium, in the thermo nuclear reaction, the Energy released in the reaction is: (A)  63× 1020 J  (B)  63× 1014 J  (C)  63× 1010 J  (D)  63× 107 J

Tardigrade Admin · Accepted Answer

Einstein's mass-energy relation gives the conversion of mass into energy.
If a substance loses an amount

Δ m

of its mass, an Equivalent amount

Δ E

of energy is produced.

Δ E = (Δ m) c^{2}

Where

c

is speed of light.
This is Einstein's mass energy relation.
Given,

m_{1} = 1 g = 1 \times 1 0^{- 3} k g

m_{2} = 0.993 g = 0.993 \times 1 0^{- 3} k g

∴ Δ m = m_{1} - m_{2} = (1 \times 1 0^{- 3}) - (0.993 \times 1 0^{- 3})

= 0.007 \times 1 0^{- 3}

= 7 \times 1 0^{- 6} k g

E = 7 \times 1 0^{- 6} \times (3 \times 1 0^{8})^{2}

E = 63 \times 1 0^{10} J

Q. If $1 g$ of hydrogen is converted into $0.993 g$ of Helium, in the thermo nuclear reaction, the Energy released in the reaction is:

$63 \times 10^{20} J$

$63 \times 10^{14} J$

$63 \times 10^{10} J$

$63 \times 10^{7} J$

Q. If 1g of hydrogen is converted into 0.993g of Helium, in the thermo nuclear reaction, the Energy released in the reaction is:

63×1020J

63×1014J

63×1010J

63×107J

Q. If $1 g$ of hydrogen is converted into $0.993 g$ of Helium, in the thermo nuclear reaction, the Energy released in the reaction is:

$63 \times 10^{20} J$

$63 \times 10^{14} J$

$63 \times 10^{10} J$

$63 \times 10^{7} J$