Question

If $1gcm{s}^{-1}=x$ newton-sec, then the number $x$ is equal to

• A. $1\times 10^{-3}$
• B. $3.6\times 10^{-3}$
• C. $1\times 10^{-5}$
• D. $6\times 10^{-4}$

Answer 1

Answer: (C)

As, $x=\frac{1gcm{s}^{-1}}{T^2}$
$=\frac{1gcm{s}^{-1}}{1kg\times 1m{s}^{-1}\times 1s}$
$=\frac{1gcm{s}^{-1}}{10^{3}g\times 10^{2}cm{s}^2\times 1s}=10^{-5}$