Question

If $1\, g\, cm s ^{-1}=x$ newton-sec, then the number $x$ is equal to

• A. $1 \times 10^{-3}$
• B. $3.6 \times 10^{-3}$
• C. $1 \times 10^{-5}$
• D. $6 \times 10^{-4}$

Answer 1

Answer: (C)

As, $x=\frac{1\, g\, cm\, s ^{-1}}{ T ^{2}} $
$=\frac{1\, g\, cm\, s ^{-1}}{1\, kg \times 1\, ms ^{-1} \times 1\, s } $
$=\frac{1\, g\, cms ^{-1}}{10^{3} g \times 10^{2} cms ^{2} \times 1\, s }=10^{-5}$