Let x be the first term and y be the c.d. of corresponding A.P., then a1=x+(p−1)y......(i) b1=x+(q−1)y......(ii) c1=x+(r−1)y.....(iii)
Multiplying (i), (ii) and (iii) respectively by abc(q−r),abc(r−p),abc(p−q) and then adding,
we get, bc(q−r)+ca(r−p)+ab(p−q)=0