If 0.5 g of a mixture of two metals A and B with respective equivalent weights 12 and 9 displace 560 mL of H 2 at STP from an acid, the composition of the mixture is

Question

If 0.5 g of a mixture of two metals A and B with respective equivalent weights 12 and 9 displace 560 mL of H 2 at STP from an acid, the composition of the mixture is (A) 40 % A , 60 % B (B) 60 % A , 40 % B (C) 30 % A , 70 % B (D) 70 % A , 30 % B

Tardigrade Admin · Accepted Answer

1 mol of 2=22400 mL =2 Eq of H 2 1 Eq of H 2=11200 mL Eq of H 2=(560/11200)=(1/20) Eq [Let the weight of A be x g; weight of B =0.5-x ] Eq of A + Eq of B = Eq of H 2 (x/12)+(0.5-x/9)=(1/20) ∴ x=0.2 % of A =(0.2 × 100/0.5)=40 % % of B =60 %

Q. If $0.5 g$ of a mixture of two metals A and B with respective equivalent weights $12$ and $9$ displace $560 m L$ of $H_{2}$ at STP from an acid, the composition of the mixture is

$40% A, 60% B$

$60% A, 40% B$

$30% A, 70% B$

$70% A, 30% B$

Q. If 0.5g of a mixture of two metals A and B with respective equivalent weights 12 and 9 displace 560mL of H2​ at STP from an acid, the composition of the mixture is

40%A,60%B

60%A,40%B

30%A,70%B

70%A,30%B

1molof2​=22400mL=2Eq of H2​ 1Eq of H2​=11200mL Eq of H2​=11200560​=201​Eq [Let the weight of A be x g; weight of B=0.5−x ] Eq of A+Eq of B= Eq of H2​ 12x​+90.5−x​=201​ ∴x=0.2 % of A=0.50.2×100​=40% % of B=60%

Q. If $0.5 g$ of a mixture of two metals A and B with respective equivalent weights $12$ and $9$ displace $560 m L$ of $H_{2}$ at STP from an acid, the composition of the mixture is

$40% A, 60% B$

$60% A, 40% B$

$30% A, 70% B$

$70% A, 30% B$