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  4. If 0.5 g of a mixture of two metals A and B with respective equivalent weights 12 and 9 displace 560 mL of H 2 at STP from an acid, the composition of the mixture is

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Q. If $0.5\, g$ of a mixture of two metals A and B with respective equivalent weights $12$ and $9$ displace $560 \,mL$ of $H _2$ at STP from an acid, the composition of the mixture is

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Solution:

$1 \,mol \,of _2=22400 \,mL =2 \,Eq$ of $H _2$
$1 \, Eq$ of $H _2=11200 \,mL$
Eq of $H _2=\frac{560}{11200}=\frac{1}{20} Eq$
[Let the weight of A be $x$ g; weight of $B =0.5-x$ ]
Eq of $A + Eq$ of $B =$ Eq of $H _2$
$\frac{x}{12}+\frac{0.5-x}{9}=\frac{1}{20} $
$\therefore x=0.2$
$\%$ of $A =\frac{0.2 \times 100}{0.5}=40 \%$
$\%$ of $B =60 \%$