Identify the total number of atoms in product Q in the given sequence of reaction C 6 H 5 NH 2 xrightarrow NaNO 2+ HCl X xrightarrow Cu 2( CN )2Y xrightarrow H 2 O / H + Z xrightarrow NaOH / CaO , ΔP xrightarrow Cl 2, text hvExcess Q

Question

Identify the total number of atoms in product Q in the given sequence of reaction C 6 H 5 NH 2 xrightarrow NaNO 2+ HCl X xrightarrow Cu 2( CN )2Y xrightarrow H 2 O / H + Z xrightarrow NaOH / CaO , ΔP xrightarrow Cl 2, text hvExcess Q (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

C 6 H 5 NH 2 xrightarrow NaNO 2 / HCl C 6 H 5 N 2+ Cl - xrightarrow Cu 2( CN )2 C 6 H 5 CN xrightarrow H 2 O / H + C 6 H 5 COOH C 6 H 5 COOH xrightarrow NaOH / CaO , ΔC 6 H 6 xrightarrow Cl 2, hv text (Excess) C 6 H 6 Cl 6 It is diazotisation reaction to produce X, then sandmayer's reaction to give Y, followed by hydrolysis to produce benzoic acid (Z). Benzoic acid on decarboxylation gives benzene, which on excess photochlorination gives benzene hexachloride.

Q. Identify the total number of atoms in product Q in the given sequence of reaction C6​H5​NH2​NaNO2​+HCl​XCu2​(CN)2​​YH2​O/H+​Z NaOH/CaO,Δ​PCl2​, hvExcess ​Q

Q. Identify the total number of atoms in product $Q$ in the given sequence of reaction
$C_{6} H_{5} N H_{2} N a N O_{2} + H Cl X C u_{2} (CN)_{2} Y H_{2} O / H^{+} Z$

$N a O H / C a O, Δ P C l_{2}, hvExcess Q$