Identify the redox reaction taking place in a beaker.

Question

Identify the redox reaction taking place in a beaker. (A) Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s) (B) Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s) (C) Cu(s) + Zn2+(aq) → Zn(s) + Cu2+(aq) (D) 2Ag(s) + Cu2+(aq) → 2Ag+(aq) + Cu(s)

Tardigrade Admin · Accepted Answer

Since copper is more reactive than silver, it displaces Ag+ ions from its salt solution which get deposited on the copper rod.

Q. Identify the redox reaction taking place in a beaker.

$Z n_{(s)} + C u_{(a q)}^{2 +} \to Z n_{(a q)}^{2 +} + C u_{(s)}$

$C u_{(s)} + 2 A g_{(a q)}^{+} \to C u_{(a q)}^{2 +} + 2 A g_{(s)}$

$C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}$

$2 A g_{(s)} + C u_{(a q)}^{2 +} \to 2 A g_{(a q)}^{+} + C u_{(s)}$

Since copper is more reactive than silver, it displaces $A g^{+}$ ions from its salt solution which get deposited on the copper rod.

Q. Identify the redox reaction taking place in a beaker.

Zn(s)​+Cu(aq)2+​→Zn(aq)2+​+Cu(s)​

Cu(s)​+2Ag(aq)+​→Cu(aq)2+​+2Ag(s)​

Cu(s)​+Zn(aq)2+​→Zn(s)​+Cu(aq)2+​