Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Identify the reactant X and the product Y. CH3 - CO - CH3 + X longrightarrow (CH3)3 C - OMgCl xrightarrowHydrolysis Y + Mg(OH)CI
Q. Identify the reactant X and the product Y.
C
H
3
−
CO
−
C
H
3
+
X
⟶
(
C
H
3
)
3
C
−
OM
g
Cl
Hy
d
ro
l
ys
i
s
Y
+
M
g
(
O
H
)
C
I
2073
199
KEAM
KEAM 2003
Aldehydes Ketones and Carboxylic Acids
Report Error
A
X
=
M
g
C
l
2
;
Y
=
C
H
3
C
H
=
C
H
2
B
X
=
C
H
3
M
g
Cl
;
Y
=
C
2
H
5
COC
H
3
C
X
=
C
H
5
M
g
Cl
;
Y
=
(
C
H
3
)
3
C
−
O
H
D
X
=
C
2
H
5
M
g
Cl
;
Y
=
(
C
H
3
)
3
C
−
O
H
E
X
=
M
g
Cl
(
O
H
)
;
Y
=
(
C
H
3
)
2
C
H
O
H
Solution:
Correct answer is (d)
X
=
C
2
H
5
M
g
Cl
;
Y
=
(
C
H
3
)
3
C
−
O
H