Question

Identify the missing product in the given nuclear reaction

${}_{92}^{235}\mathrm{U}+{}_0^1\mathrm{n}\to ?+{}_{36}^{92}\mathrm{Kr}+3{}_0^1\mathrm{n}$

• A. ${}_{56}^{141}\mathrm{Ba}$
• B. ${}_{56}^{139}\mathrm{Ba}$
• C. ${}_{54}^{139}\mathrm{Ba}$
• D. ${}_{54}^{141}\mathrm{Ba}$

Answer 1

Answer: (A)

By Mass Conservation
$92+0=Z+36+0$
$Z=56$
$235+1=A+92+3$
$A=141$
Missing nuclear is ${}_{56}^{141}Ba$ .