Question

Identify the missing product in the given nuclear reaction

${ }_{92}^{235} \mathrm{U}+{ }_0^1 \mathrm{n} \rightarrow ?+{ }_{36}^{92} \mathrm{Kr}+3{ }_0^1 \mathrm{n}$

• A. ${ }_{56}^{141} \mathrm{Ba}$
• B. ${ }_{56}^{139} \mathrm{Ba}$
• C. ${ }_{54}^{139} \mathrm{Ba}$
• D. ${ }_{54}^{141} \mathrm{Ba}$

Answer 1

Answer: (A)

By Mass Conservation
$92+0=Z+36+0$
$Z=56$
$235+1=A+92+3$
$A=141$
Missing nuclear is $_{56}^{141}Ba$ .