Identify the correct statement with respect to the following reaction, 2K2MnO4 + Cl2 → 2KCl + 2KMnO4

Question

Identify the correct statement with respect to the following reaction, 2K2MnO4 + Cl2 → 2KCl + 2KMnO4 (A) Oxidation of potassium manganate is taking place. (B) Reduction of potassium manganate is taking place. (C) Oxidation of Cl2 is taking place. (D) Cl2 acts as reducing agent in the reaction.

Tardigrade Admin · Accepted Answer

2K2 overset text+6MnO4 + overset text0Cl2 → 2K overset text-1Cl+ overset text+72KMnO4 Mn → Increase in oxidation number hence oxidation. Cl2 → Decrease in oxidation number hence reduction. Cl2 is acting as an oxidising agent.

Q. Identify the correct statement with respect to the following reaction, $2 K_{2} M n O_{4} + C l_{2} \to 2 K Cl + 2 K M n O_{4}$

Oxidation of potassium manganate is taking place.

Reduction of potassium manganate is taking place.

Oxidation of $C l_{2}$ is taking place.

$C l_{2}$ acts as reducing agent in the reaction.

$2 K_{2} M n +6 O_{4} + C 0 l_{2} \to 2 K Cl -1 + 2 K M n O_{4} +7$
$M n$ → Increase in oxidation number hence oxidation.
$C l_{2}$ → Decrease in oxidation number hence reduction.
$C l_{2}$ is acting as an oxidising agent.

Q. Identify the correct statement with respect to the following reaction, 2K2​MnO4​+Cl2​→2KCl+2KMnO4​

Oxidation of potassium manganate is taking place.

Reduction of potassium manganate is taking place.

Oxidation of Cl2​ is taking place.

Cl2​ acts as reducing agent in the reaction.

2K2​Mn+6O4​+C0l2​→2KCl-1+2KMnO4​+7​ Mn → Increase in oxidation number hence oxidation. Cl2​ → Decrease in oxidation number hence reduction. Cl2​ is acting as an oxidising agent.

Q. Identify the correct statement with respect to the following reaction, $2 K_{2} M n O_{4} + C l_{2} \to 2 K Cl + 2 K M n O_{4}$

Oxidation of $C l_{2}$ is taking place.

$C l_{2}$ acts as reducing agent in the reaction.

$2 K_{2} M n +6 O_{4} + C 0 l_{2} \to 2 K Cl -1 + 2 K M n O_{4} +7$
$M n$ → Increase in oxidation number hence oxidation.
$C l_{2}$ → Decrease in oxidation number hence reduction.
$C l_{2}$ is acting as an oxidising agent.