Identify the correct order of the size of the following.

Question

Identify the correct order of the size of the following. (A) Ca2+ < K+ < Ar < S2- < Cl- (B) Ca2+ < K+ < Ar < Cl- < S2- (C) Ar < Ca2+ < K+ < Cl- < S2- (D) Ca2+ < Ar < K+ < Cl- < S2-

Tardigrade Admin · Accepted Answer

A cation has always the lesser ionic size than a metal atom due to loss of electrons and an anion has always the greater size than metal atom due to gain of electrons. So, the correct order of size is as

C a^{2 +} < K^{+} < A r < C l^{-} < S^{2 -}

Q. Identify the correct order of the size of the following.

$C a^{2 +} < K^{+} < A r < S^{2 -} < C l^{-}$

$C a^{2 +} < K^{+} < A r < C l^{-} < S^{2 -}$

$A r < C a^{2 +} < K^{+} < C l^{-} < S^{2 -}$

$C a^{2 +} < A r < K^{+} < C l^{-} < S^{2 -}$

A cation has always the lesser ionic size than a metal atom due to loss of electrons and an anion has always the greater size than metal atom due to gain of electrons. So, the correct order of size is as
$C a^{2 +} < K^{+} < A r < C l^{-} < S^{2 -}$

Q. Identify the correct order of the size of the following.

Ca2+<K+<Ar<S2−<Cl−

Ca2+<K+<Ar<Cl−<S2−

Ar<Ca2+<K+<Cl−<S2−

Ca2+<Ar<K+<Cl−<S2−

A cation has always the lesser ionic size than a metal atom due to loss of electrons and an anion has always the greater size than metal atom due to gain of electrons. So, the correct order of size is as Ca2+<K+<Ar<Cl−<S2−

$C a^{2 +} < K^{+} < A r < S^{2 -} < C l^{-}$

$C a^{2 +} < K^{+} < A r < C l^{-} < S^{2 -}$

$A r < C a^{2 +} < K^{+} < C l^{-} < S^{2 -}$

$C a^{2 +} < A r < K^{+} < C l^{-} < S^{2 -}$

A cation has always the lesser ionic size than a metal atom due to loss of electrons and an anion has always the greater size than metal atom due to gain of electrons. So, the correct order of size is as
$C a^{2 +} < K^{+} < A r < C l^{-} < S^{2 -}$