Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali.

Question

Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

underset1° textamineR - NH - H + underset textHinsberg reagentSO2C6H5 → underset textN - alkyl benzene Sulphonamide alkali solubleR - NHSO2C6H5 + HCl H - atom attached to nitrogen is highly acidic because it is attached to strong electron withdrawing - SO 2 C 6 H 5 group

Q. Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali.

$1^{\circ} amine R - N H - H + Hinsberg reagent S O_{2} C_{6} H_{5} \to N - alkyl benzene Sulphonamide alkali soluble R - N H S O_{2} C_{6} H_{5} + H Cl$
$H$ - atom attached to nitrogen is highly acidic because it is attached to strong electron withdrawing $- S O_{2} C_{6} H_{5}$ group

Q. Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali.

1∘amineR−NH−H​+Hinsberg reagentSO2​C6​H5​​→N - alkyl benzene Sulphonamide alkali solubleR−NHSO2​C6​H5​​+HCl H - atom attached to nitrogen is highly acidic because it is attached to strong electron withdrawing −SO2​C6​H5​ group

$1^{\circ} amine R - N H - H + Hinsberg reagent S O_{2} C_{6} H_{5} \to N - alkyl benzene Sulphonamide alkali soluble R - N H S O_{2} C_{6} H_{5} + H Cl$
$H$ - atom attached to nitrogen is highly acidic because it is attached to strong electron withdrawing $- S O_{2} C_{6} H_{5}$ group