Ideal gas undergoes an adiabatic change in its state from (p1, V1, T1) to (p2, V2, T2). The work done (W) in the process is ( μ= number of molecules, CP and CV are molar specific heats of gas)

Question

Ideal gas undergoes an adiabatic change in its state from (p1, V1, T1) to (p2, V2, T2). The work done (W) in the process is ( μ= number of molecules, CP and CV are molar specific heats of gas) (A) W=μ CP(T1-T2) (B) W=μ CV(T1-T2) (C) W=μ CP(T1+T2) (D) W=μ CV(T1+T2)

Tardigrade Admin · Accepted Answer

In adiabatic change work done W=μ Cp Δ T or W=μ Cp(T1-T2)

Q. Ideal gas undergoes an adiabatic change in its state from $(p_{1}, V_{1}, T_{1})$ to $(p_{2}, V_{2}, T_{2})$ . The work done $(W)$ in the process is ( $μ =$ number of molecules, $C_{P}$ and $C_{V}$ are molar specific heats of gas)

$W = μ C_{P} (T_{1} - T_{2})$

$W = μ C_{V} (T_{1} - T_{2})$

$W = μ C_{P} (T_{1} + T_{2})$

$W = μ C_{V} (T_{1} + T_{2})$

In adiabatic change work done
$W = μ C_{p} Δ T$
or $W = μ C_{p} (T_{1} - T_{2})$

Q. Ideal gas undergoes an adiabatic change in its state from (p1​,V1​,T1​) to (p2​,V2​,T2​). The work done (W) in the process is ( μ= number of molecules, CP​ and CV​ are molar specific heats of gas)

W=μCP​(T1​−T2​)

W=μCV​(T1​−T2​)

W=μCP​(T1​+T2​)

W=μCV​(T1​+T2​)