Question

Iceberg floats in sea water with a part of it submerged. The percentage fraction of the ice berg submerged is (Density of ice $=0.9gc{m}^{-3}$, density of sea water $=1.1gc{m}^{-3}$)

• A. $18\%$
• B. $12\%$
• C. $10\%$
• D. $8\%$

Answer 1

Answer: (A)

$V$ be the volume of the iceberg, $x$ be the volume out of sea water
The iceberg is floating in sea water then
$V{\rho }_{ice}g=\left(V-x\right){\rho }_{seawater}g$
or $V\times 0.9\times g=\left(V-x\right)1.1g$
or $0.9V=1.1V-1.1x$
$0.2V=1.1x$
$\therefore \frac{x}{V}=\frac{0.2}{1.1}$
Percentage of fraction of the volume of iceberg above thelevel of sea water
$\frac{x}{V}\times 100=\frac{0.2}{1.1}\times 100$
$=18\%$