I2(s)|.I-(0 . 1 M) half cell is connected to a H+(.aq.)|.H2(1 bar),Pt half cell and e.m.f. is found to be 0.7714V . If EI2 / I-o=0.535V , find the pH of H+|.H2,Pt half cell.

Question

I2(s)|.I-(0 . 1 M) half cell is connected to a H+(.aq.)|.H2(1 bar),Pt half cell and e.m.f. is found to be 0.7714V . If EI2 / I-o=0.535V , find the pH of H+|.H2,Pt half cell. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The cell reaction is H2 (. g .)+I2 (. s .)leftharpoons2H(. a q .)++2I(. a q .)- Here n=2 (n = number of electons involved ) E=E° -(0.0591/n)log([. H+ ].2 [. I- ].2/PH2) 0.7714=0.535-(0.0591/2)log([. H+ ].2 [. 0.1 ].2/1) On solving (.H+.)=10- 3 pH=-log(.H+.)=-log(.10- 3.) So pH=3

Q. I2​(s)∣I−(0.1M) half cell is connected to a H+(aq)∣H2​(1bar),Pt half cell and e.m.f. is found to be 0.7714V . If EI2​/I−o​=0.535V , find the pH of H+∣H2​,Pt half cell.

The cell reaction is H2(g)​+I2(s)​⇌2H(aq)+​+2I(aq)−​ Here n=2 (n = number of electons involved ) E=E∘−n0.0591​logPH2​​[H+]2[I−]2​ 0.7714=0.535−20.0591​log1[H+]2[0.1]2​ On solving (H+)=10−3 pH=−log(H+)=−log(10−3) So pH=3

Q. $I_{2} (s) ∣ I^{-} (0.1 M)$ half cell is connected to a $H^{+} (a q) ∣ H_{2} (1 ba r), Pt$ half cell and e.m.f. is found to be $0.7714 V$ . If $E_{I_{2} / I^{-}}^{o} = 0.535 V$ , find the $p H$ of $H^{+} ∣ H_{2}, Pt$ half cell.