Question

$i^2+i^4+i^6+...(2n+1)$ terms =

• A. $1$
• B. $-1$
• C. $i$
• D. $-i$

Answer 1

Answer: (B)

The first $2n$ terms will cancel in pairs and the last term is
${\left(i^2\right)}^{2n+1}=i^{4n}\cdot i^2$
$=-1$