(I) 1,2-Dihydroxy benzene (II) 1,3-Dihydroxy benzene (III) 1,4-Dihydroxy benzene (IV) Hydroxy benzene The increasing order of boiling points of the above mentioned alcohols is

Question

(I) 1,2-Dihydroxy benzene (II) 1,3-Dihydroxy benzene (III) 1,4-Dihydroxy benzene (IV) Hydroxy benzene The increasing order of boiling points of the above mentioned alcohols is (A) I < II < III < IV (B) I < II < IV < III (C) IV < I < II < III (D) IV < II < I < III

Tardigrade Admin · Accepted Answer

The structures of the given compounds are as follows:

We know that the boiling point increases as molecular mass increases so

I V

has the least boiling point. Also, among the isomeric alcohols, paraisomer has the highest value of boiling point being symmetrical in nature; followed by meta- and then ortho-isomers.
Hence, the correct order of boiling points is

∣ V < I < II < II

.

Q. (I) $1, 2$ -Dihydroxy benzene
(II) $1, 3$ -Dihydroxy benzene
(III) $1, 4$ -Dihydroxy benzene
(IV) Hydroxy benzene
The increasing order of boiling points of the above mentioned alcohols is

$I < II < III < I V$

$I < II < I V < III$

$I V < I < II < III$

$I V < II < I < III$

Q. (I) 1,2-Dihydroxy benzene (II) 1,3-Dihydroxy benzene (III) 1,4-Dihydroxy benzene (IV) Hydroxy benzene The increasing order of boiling points of the above mentioned alcohols is

I<II<III<IV

I<II<IV<III

IV<I<II<III

IV<II<I<III

Q. (I) $1, 2$ -Dihydroxy benzene
(II) $1, 3$ -Dihydroxy benzene
(III) $1, 4$ -Dihydroxy benzene
(IV) Hydroxy benzene
The increasing order of boiling points of the above mentioned alcohols is

$I < II < III < I V$

$I < II < I V < III$

$I V < I < II < III$

$I V < II < I < III$