Hydrolysis of BCl3 gives X, which on treatment with sodium carbonate produces Y, X and Y, respectively, are

Question

Hydrolysis of BCl3 gives X, which on treatment with sodium carbonate produces Y, X and Y, respectively, are (A) H3BO3 and NaBO2 (B) H3BO3 and Na2B4O7 (C) B2O3 and NaBO2 (D) B2O3 and Na2B4O7

Tardigrade Admin · Accepted Answer

Hydrolysis of BCl3 gives boric acid (X), which on treatment with sodium carbonate produces sodium metaborate (F), carbon dioxide and water BCl 3+3 H 2 O longrightarrow H 3 undersetX B O 3+3 HCl 4 H 3 BO 3+ Na 2 CO 3 longrightarrow undersetYNa 2 B 4 O 7+ CO 2+6 H 2 O

Q. Hydrolysis of $BC l_{3}$ gives $X$ , which on treatment with sodium carbonate produces $Y, X$ and $Y$ , respectively, are

$H_{3} B O_{3}$ and $N a B O_{2}$

$H_{3} B O_{3}$ and $N a_{2} B_{4} O_{7}$

$B_{2} O_{3}$ and $N a B O_{2}$

$B_{2} O_{3}$ and $N a_{2} B_{4} O_{7}$

Hydrolysis of $BC l_{3}$ gives boric acid $(X)$ , which on treatment with sodium carbonate produces sodium metaborate $(F)$ , carbon dioxide and water
$BC l_{3} + 3 H_{2} O ⟶ H_{3} X B O_{3} + 3 H Cl$
$4 H_{3} B O_{3} + N a_{2} C O_{3} ⟶$
$Y N a_{2} B_{4} O_{7} + C O_{2} + 6 H_{2} O$

Q. Hydrolysis of BCl3​ gives X, which on treatment with sodium carbonate produces Y,X and Y, respectively, are

H3​BO3​ and NaBO2​

H3​BO3​ and Na2​B4​O7​

B2​O3​ and NaBO2​

B2​O3​ and Na2​B4​O7​